You can not select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.

54 lines
2.0 KiB

\documentclass[11pt,English]{article}
\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage[bottom]{footmisc}
% Keywords command
\providecommand{\keywords}[1]
{
\small
\-\ \-\ \-\ \textbf{\textit{Keywords --}} #1
}
% Slides
%
% 1) Authors names and affiliations
% 2) Title abstract keywords
% 3) 147 why its important
\title{
Green's Theorem\\
\large Historical Origins and Analytical Applications\\
\small MATH 147 Final Project\\
\small University of Kansas, Dept. of Mathematics
}
\author{
Atkins, Thomas\\
\texttt{thomas.atkins@ku.edu}
\and
Mills, Garrett\\
\texttt{glmdev@ku.edu}
\and
Weng, QiTao\\
\texttt{wengqt@ku.edu}
}
\date{December 2019}
\begin{document}
\maketitle
\begin{abstract}
In which the authors investigate the historical origins and several mathematical applications of the commonly known Green's theorem. Discovered by George Green in the late 1820s, this theorem provides a relationship between the line integral of a particular curve and the surface integral of its enclosed region. Green's theorem is closely related to the divergence theorem, and is simply a specific case of the more general Stoke's theorem. Beyond basic applications to flux and surface integrals, Green's theorem can be reverse applied to calculate difficult-to-evaluate area calculations. It also plays an integral role (pun intended) in the proof of other important theorems such as Cauchy's.
\end{abstract}
\keywords{Green, Stoke, integration, vector calculus}
\section{Introduction}
Green's theorem is commonly defined as follows.\footnote{"Section 5-7: Green's Theorem" - Paul Dawkins, Lamar University - 02-22-2019. (http://tutorial.math.lamar.edu/Classes/CalcIII/GreensTheorem.aspx)} Let $C$ be a simple, smooth, closed, positive curve and $D$ the region enclosed by said curve. Assume $P'$, $Q'$ are continuous. Then, the following relationship holds:
$$
\int_C{ P dx + Q dy } = \iint_D{ \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) dA }
$$
\end{document}