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lesson 3, boot sector with memory addressing
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*Concepts you may want to Google beforehand: memory offsets, pointers*
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*Concepts you may want to Google beforehand: memory offsets, pointers*
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The only goal of this lesson is to learn where the boot sector is stored
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Please open page 14 [of this document](
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Please open page 14 [of this document](
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http://www.cs.bham.ac.uk/~exr/lectures/opsys/10_11/lectures/os-dev.pdf)<sup>1</sup>
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http://www.cs.bham.ac.uk/~exr/lectures/opsys/10_11/lectures/os-dev.pdf)<sup>1</sup>
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and look at the figure with the memory layout.
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and look at the figure with the memory layout.
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I could just go ahead and tell you that it starts at `0x7C00`, but it's
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The only goal of this lesson is to learn where the boot sector is stored
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better with an example.
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I could just go ahead and tell you that the BIOS places it at `0x7C00`, but an
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example with wrong solutions will make things clearer.
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We want to print an X on screen. We will try 4 different strategies
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We want to print an X on screen. We will try 4 different strategies
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and see which ones work and why.
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and see which ones work and why.
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@ -23,7 +23,7 @@ Then we will try to access `the_secret` in many different ways:
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1. `mov al, the_secret`
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1. `mov al, the_secret`
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2. `mov al, [the_secret]`
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2. `mov al, [the_secret]`
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3. `mov al, the_secret + 0x7C00`
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3. `mov al, the_secret + 0x7C00`
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4. `mov al, 2d + 0x7C00`, where `2d` is the actual position of the X in the binary
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4. `mov al, 2d + 0x7C00`, where `2d` is the actual position of the 'X' byte in the binary
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Take a look at the code and read the comments.
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Take a look at the code and read the comments.
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@ -33,6 +33,21 @@ the bytes following 1 and 2 are just random garbage.
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If you add or remove instructions, remember to compute the new offset of the X
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If you add or remove instructions, remember to compute the new offset of the X
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by counting the bytes, and replace `0x2d` with the new one.
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by counting the bytes, and replace `0x2d` with the new one.
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Please don't continue onto the next file unless you have 100% understood
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the boot sector offset and memory addressing.
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Now, since offsetting `0x7c00` everywhere is very inconvenient, assemblers let
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us define a "global offset" for every memory location, with the `org` command:
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```nasm
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[org 0x7c00]
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```
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Go ahead and open `boot_sect_memory_org.asm` and you will see the canonical
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way to print data with the boot sector, which is now attempt 2. Compile the code
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and run it, and you will see how the `org` command affects each previous solution.
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Read the comments for a full explanation of the changes with and without `org`
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-----
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-----
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@ -10,7 +10,7 @@ int 0x10
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; attempt 2
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; attempt 2
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; It tries to print the memory address of 'the_secret' which is the correct approach.
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; It tries to print the memory address of 'the_secret' which is the correct approach.
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; However, BIOS starts loading at address 0x7c00
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; However, BIOS places our bootsector binary at address 0x7c00
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; so we need to add that padding beforehand. We'll do that in attempt 3
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; so we need to add that padding beforehand. We'll do that in attempt 3
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mov al, "2"
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mov al, "2"
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int 0x10
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int 0x10
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@ -19,7 +19,9 @@ int 0x10
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; attempt 3
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; attempt 3
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; Add the BIOS starting offset 0x7c00 to the memory address of the X
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; Add the BIOS starting offset 0x7c00 to the memory address of the X
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; and then dereference the contents of that pointer
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; and then dereference the contents of that pointer.
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; We need the help of a different register 'bx' because 'mov al, [ax]' is illegal.
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; A register can't be used as source and destination for the same command.
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mov al, "3"
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mov al, "3"
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int 0x10
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int 0x10
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mov bx, the_secret
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mov bx, the_secret
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@ -29,19 +31,21 @@ int 0x10
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; attempt 4
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; attempt 4
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; We try a shortcut since we know that the X is stored at byte 0x2d in our binary
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; We try a shortcut since we know that the X is stored at byte 0x2d in our binary
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; That's smart but ineffective, we don't want to be recounting label offsets
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; every time we change the code
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mov al, "4"
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mov al, "4"
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int 0x10
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int 0x10
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mov al, [0x7c2d]
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mov al, [0x7c2d]
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int 0x10
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int 0x10
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jmp $
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jmp $ ; infinite loop
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the_secret:
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the_secret:
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; ASCII code 0x58 is stored just before the zero-padding
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; ASCII code 0x58 ('X') is stored just before the zero-padding.
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; on this code that is at byte 0x2d (check it out using xdd)
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; On this code that is at byte 0x2d (check it out using 'xdd file.bin')
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db "X"
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db "X"
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; zero padding and magic bios number
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times 510-($-$$) db 0
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times 510-($-$$) db 0
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dw 0xaa55
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dw 0xaa55
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47
03-bootsector-memory/boot_sect_memory_org.asm
Normal file
47
03-bootsector-memory/boot_sect_memory_org.asm
Normal file
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[org 0x7c00]
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mov ah, 0x0e
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; attempt 1
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; Will fail again regardless of 'org' because we are still addressing the pointer
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; and not the data it points to
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mov al, "1"
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int 0x10
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mov al, the_secret
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int 0x10
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; attempt 2
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; Having solved the memory offset problem with 'org', this is now the correct answer
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mov al, "2"
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int 0x10
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mov al, [the_secret]
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int 0x10
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; attempt 3
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; As you expected, we are adding 0x7c00 twice, so this is not going to work
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mov al, "3"
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int 0x10
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mov bx, the_secret
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add bx, 0x7c00
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mov al, [bx]
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int 0x10
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; attempt 4
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; This still works because there are no memory references to pointers, so
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; the 'org' mode never applies. Directly addressing memory by counting bytes
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; is always going to work, but it's inconvenient
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mov al, "4"
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int 0x10
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mov al, [0x7c2d]
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int 0x10
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jmp $ ; infinite loop
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the_secret:
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; ASCII code 0x58 ('X') is stored just before the zero-padding.
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; On this code that is at byte 0x2d (check it out using 'xdd file.bin')
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db "X"
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; zero padding and magic bios number
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times 510-($-$$) db 0
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dw 0xaa55
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