From 2e0ff5b0c22c690ddae087cfedd0aa62617e94de Mon Sep 17 00:00:00 2001 From: Thomas N Atkins Date: Sun, 1 Dec 2019 15:39:30 -0600 Subject: [PATCH] Add abstract and basic introduction --- main.tex | 32 ++++++++++++++++++++++++++++---- 1 file changed, 28 insertions(+), 4 deletions(-) diff --git a/main.tex b/main.tex index 2db0036..d557668 100644 --- a/main.tex +++ b/main.tex @@ -1,14 +1,38 @@ -\documentclass{article} +\documentclass[11pt,English]{article} \usepackage[utf8]{inputenc} +\usepackage{amsmath} +\usepackage[bottom]{footmisc} -\title{Math 147 Final Project} -\author{Thomas Atkins} -\date{November 2019} +\title{ +Green's Theorem\\ + \large Historical Origins and Analytical Applications\\ + \small MATH 147 Final Project\\ + \small University of Kansas, Dept. of Mathematics +} +\author{ + Atkins, Thomas\\ + \texttt{thomas.atkins@ku.edu} + \and + Mills, Garrett\\ + \texttt{glmdev@ku.edu} + \and + Weng, QiTao\\ + \texttt{wengqt@ku.edu} +} +\date{December 2019} \begin{document} \maketitle +\begin{abstract} + In which the authors investigate the historical origins and several mathematical applications of the commonly known Green's theorem. Discovered by George Green in the late 1820s, this theorem provides a relationship between the line integral of a particular curve and the surface integral of its enclosed region. Green's theorem is closely related to the divergence theorem, and is simply a specific case of the more general Stoke's theorem. Beyond basic applications to flux and surface integrals, Green's theorem can be reverse applied to calculate difficult-to-evaluate area calculations. It also plays an integral role (pun intended) in the proof of other important theorems such as Cauchy's. +\end{abstract} \section{Introduction} +Green's theorem is commonly defined as follows.\footnote{"Section 5-7: Green's Theorem" - Paul Dawkins, Lamar University - 02-22-2019. (http://tutorial.math.lamar.edu/Classes/CalcIII/GreensTheorem.aspx)} Let $C$ be a simple, smooth, closed, positive curve and $D$ the region enclosed by said curve. Assume $P'$, $Q'$ are continuous. Then, the following relationship holds: +$$ +\int_C{ P dx + Q dy } = \iint_D{ \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) dA } +$$ + \end{document}